2v^2-15v+7=0

Solution for 2v^2-15v+7=0 equation:

2v^2-15v+7=0

a = 2; b = -15; c = +7;
Δ = b2-4ac
Δ = -152-4·2·7
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-13}{2*2}=\frac{2}{4}
=1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+13}{2*2}=\frac{28}{4}
=7
$